What is the tangent of x^2+x,\at x=-1 ?

The tangent of x^2+x,\at x=-1 is y=-x-1

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tangent of x^2+x,\at x=-1

tangent of

x^{2} + x, at x = - 1

y = - x - 1

Solution steps

Find the tangent point:

(- 1, 0)

Find the slope of

y = x^{2} + x : \frac{d y}{d x} = 2 x + 1

Compute the slope of

y = x^{2} + x

x = - 1 : m = - 1

Find the line with slope m=

- 1

and passing through

(- 1, 0) : y = - x - 1

y = - x - 1

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