What is the derivative of f(x)=x^2-4x-5 ?

The derivative of f(x)=x^2-4x-5 is 2x-4

What is the first derivative of f(x)=x^2-4x-5 ?

The first derivative of f(x)=x^2-4x-5 is 2x-4

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derivative of

f (x) = x^{2} - 4 x - 5

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 2 x - 4 - 0

Simplify

= 2 x - 4

\int (9 + x^{5})^{7} x^{4} d x

x \to 3 + lim (2 x^{2} - 4)

(3 y^{2} + 4 x) d x + (2 y x) d y = 0

\frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}

\frac{d}{d x} (\frac{( x - 1 ) ^{2}}{( x + 2 )})

What is the derivative of f(x)=x^2-4x-5 ?
The derivative of f(x)=x^2-4x-5 is 2x-4
What is the first derivative of f(x)=x^2-4x-5 ?
The first derivative of f(x)=x^2-4x-5 is 2x-4