What is (\partial)/(\partial y)(y-2x-2) ?

The answer to (\partial)/(\partial y)(y-2x-2) is 1

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(\partial)/(\partial y)(y-2x-2)

\frac{\partial}{\partial y} (y - 2 x - 2)

1

Solution steps

\frac{\partial}{\partial y} (y - 2 x - 2)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (2 x) - \frac{\partial}{\partial y} (2)

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (2) = 0

= 1 - 0 - 0

Simplify

= 1

y = \frac{1}{x - 3}

\int \frac{( x ^{2} + 1 )}{( x - 9 ) ( x - 8 ) ^{2}} d x

\int x cos (8 x^{2}) d x

f (x) = x^{2} - 2 x + 3, at x = 2

x \to 0 lim (Q (x))

What is (\partial)/(\partial y)(y-2x-2) ?
The answer to (\partial)/(\partial y)(y-2x-2) is 1