What is the integral from 1/2 to 1 of (x^{-3}-13) ?

The integral from 1/2 to 1 of (x^{-3}-13) is -5

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integral from 1/2 to 1 of (x^{-3}-13)

\int_{\frac{1}{2}}^{1} (x^{- 3} - 13) d x

- 5

Solution steps

\int_{\frac{1}{2}}^{1} x^{- 3} - 13 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{\frac{1}{2}}^{1} x^{- 3} d x - \int_{\frac{1}{2}}^{1} 13 d x

\int_{\frac{1}{2}}^{1} x^{- 3} d x = \frac{3}{2}

\int_{\frac{1}{2}}^{1} 13 d x = \frac{13}{2}

= \frac{3}{2} - \frac{13}{2}

Simplify

\frac{3}{2} - \frac{13}{2} : - 5

= - 5

\frac{d}{d x} (4 sin (7 x))

x \to 0 lim (\frac{2 x + 1}{x + 3})

\frac{d y}{d x} = (y^{2} - 3 y)

\frac{\partial}{\partial x} (x^{\frac{1}{2}} y^{\frac{3}{2}})

\frac{d}{d x} (- \frac{4}{( x - 2 ) ^{2}})

What is the integral from 1/2 to 1 of (x^{-3}-13) ?
The integral from 1/2 to 1 of (x^{-3}-13) is -5