en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1-x^2)y^'+xy=x

Solution

(1 - x^{2}) y^{^{'}} + x y = x

Solution

y = c_{1} - x^{2} + 1 + 1

Solution steps

(1 - x^{2}) y^{'} (x) + x y = x

Solve separable ODE:

y = c_{1} - x^{2} + 1 + 1

y = c_{1} - x^{2} + 1 + 1

Popular Examples

integral of (2x)/(k^2)

\int \frac{2 x}{k ^{2}} d x

limit as x approaches infinity of x^2-4x

x \to \infty lim (x^{2} - 4 x)

derivative of f(x)=4sin^3(sqrt(x))derivative of

f (x) = 4 sin^{3} (x)

y^'+2/t y=(sin(t))/t

y^{^{'}} + \frac{2}{t} y = \frac{sin ( t )}{t}

integral of (1/(sqrt(1-x^2)))

\int (\frac{1}{1 - x ^{2}}) d x

Frequently Asked Questions (FAQ)

What is the solution for (1-x^2)y^'+xy=x ?
The solution for (1-x^2)y^'+xy=x is y=c_{1}sqrt(-x^2+1)+1