What is the solution for y^'+2/t y=(sin(t))/t ?

The solution for y^'+2/t y=(sin(t))/t is y=-(cos(t))/t+(sin(t))/(t^2)+(c_{1})/(t^2)

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y^'+2/t y=(sin(t))/t

y^{^{'}} + \frac{2}{t} y = \frac{sin ( t )}{t}

y = - \frac{cos ( t )}{t} + \frac{sin ( t )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

Solution steps

y^{'} (t) + \frac{2}{t} y = \frac{sin ( t )}{t}

Solve linear ODE:

y = - \frac{cos ( t )}{t} + \frac{sin ( t )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

y = - \frac{cos ( t )}{t} + \frac{sin ( t )}{t ^{2}} + \frac{c _{1}}{t ^{2}}

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What is the solution for y^'+2/t y=(sin(t))/t ?
The solution for y^'+2/t y=(sin(t))/t is y=-(cos(t))/t+(sin(t))/(t^2)+(c_{1})/(t^2)