What is the integral from-infinity to 12 of re^{r/4} ?

The integral from-infinity to 12 of re^{r/4} is 32e^3

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integral from-infinity to 12 of re^{r/4}

\int_{- \infty}^{12} r e^{\frac{r}{4}} d r

32 e^{3}

Decimal Notation

642.73718 \dots

Solution steps

\int_{- \infty}^{12} r e^{\frac{r}{4}} d r

Compute the indefinite integral:

\int r e^{\frac{r}{4}} d r = 4 e^{\frac{r}{4}} r - 16 e^{\frac{r}{4}} + C

Compute the boundaries:

\int_{- \infty}^{12} r e^{\frac{r}{4}} d r = 32 e^{3} - 0

= 32 e^{3} - 0

Simplify

= 32 e^{3}

y^{^{''}} + 10 y = 0

\int \frac{17 x ^{7}}{315} d x

\int \frac{cos ( x )}{3} d x

\frac{d}{d x} ((x^{2} - x + 1)^{3})

(cos (5 x)) y^{^{'}} + 5 (tan (5 x)) y = - 9 sec (5 x)

What is the integral from-infinity to 12 of re^{r/4} ?
The integral from-infinity to 12 of re^{r/4} is 32e^3