What is laplacetransform sin(2t) ?

The answer to laplacetransform sin(2t) is 2/(s^2+4)

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laplacetransform sin(2t)

laplace transform

sin (2 t)

\frac{2}{s ^{2} + 4}

Solution steps

L {sin (2 t)}

Use Laplace Transform table:

L {sin (a t)} = \frac{a}{s ^{2} + a ^{2}}

L {sin (2 t)} = \frac{2}{s ^{2} + 2 ^{2}}

= \frac{2}{s ^{2} + 2 ^{2}}

= \frac{2}{s ^{2} + 4}

\frac{d}{d x} ((x + 1)^{\frac{1}{3}})

\frac{d}{d x} (arcsec (x^{2}))

\frac{2 s}{( s + 2 )}

x \to 0 lim (\frac{2 x + 1}{x ^{2}})

f (x) = 8 + 4 x^{2} - 2 x^{3}, at x = 1

What is laplacetransform sin(2t) ?
The answer to laplacetransform sin(2t) is 2/(s^2+4)