What is the limit as x approaches 0 of (2x+1)/(x^2) ?

The limit as x approaches 0 of (2x+1)/(x^2) is infinity

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limit as x approaches 0 of (2x+1)/(x^2)

x \to 0 lim (\frac{2 x + 1}{x ^{2}})

\infty

Solution steps

x \to 0 lim (\frac{2 x + 1}{x ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{2 x + 1}{x ^{2}}) = \infty

x \to 0 + lim (\frac{2 x + 1}{x ^{2}}) = \infty

= \infty

f (x) = 8 + 4 x^{2} - 2 x^{3}, at x = 1

\int \frac{e ^{x}}{e ^{x} - 2 e ^{- x}} d x

\frac{x ^{2}}{( x ^{2} + 5 ) ^{3}}

y^{^{'}} = \frac{7 x}{y}

\int \frac{x ^{2}}{8 x ^{3} - 1} d x

What is the limit as x approaches 0 of (2x+1)/(x^2) ?
The limit as x approaches 0 of (2x+1)/(x^2) is infinity