What is the integral of 1/(2xsqrt(x)) ?

The integral of 1/(2xsqrt(x)) is -1/(sqrt(x))+C

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integral of 1/(2xsqrt(x))

\int \frac{1}{2 x x} d x

- \frac{1}{x} + C

Solution steps

\int \frac{1}{2 x x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{x x} d x

Simplify

x x : x^{\frac{3}{2}}

= \frac{1}{2} \cdot \int \frac{1}{x ^{\frac{3}{2}}} d x

Apply the Power Rule

: - \frac{2}{x}

= \frac{1}{2} (- \frac{2}{x})

Simplify

\frac{1}{2} (- \frac{2}{x}) : - \frac{1}{x}

= - \frac{1}{x}

Add a constant to the solution

= - \frac{1}{x} + C

\int ln (x) x^{13} d x

\int_{1}^{4} \frac{5}{x ^{2}} d x

\int e^{- x} (1 + e^{2 x}) d x

\frac{d}{d x} (\frac{1}{4 x + 4})

f (y) = e^{y}

What is the integral of 1/(2xsqrt(x)) ?
The integral of 1/(2xsqrt(x)) is -1/(sqrt(x))+C