What is the integral from-1 to 1 of 3/(x^2) ?

The integral from-1 to 1 of 3/(x^2) is diverges

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integral from-1 to 1 of 3/(x^2)

\int_{- 1}^{1} \frac{3}{x ^{2}} d x

diverges

Solution steps

\int_{- 1}^{1} \frac{3}{x ^{2}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 1}^{0} \frac{3}{x ^{2}} d x + \int_{0}^{1} \frac{3}{x ^{2}} d x

\int_{- 1}^{0} \frac{3}{x ^{2}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\frac{\partial}{\partial x} (L + (L^{2} + x^{2})^{\frac{1}{2}})

\frac{d}{d y} (29 - x^{2} - 4 y^{2})

\int (\frac{x}{x - 1}) d x

x^{3} - 25 x + 5, at 5

x \to 0 lim (cos (x) - 1 + x)

What is the integral from-1 to 1 of 3/(x^2) ?
The integral from-1 to 1 of 3/(x^2) is diverges