What is the tangent of f(x)=7e^x+x,(0,7) ?

The tangent of f(x)=7e^x+x,(0,7) is y=8x+7

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tangent of f(x)=7e^x+x,(0,7)

tangent of

f (x) = 7 e^{x} + x, (0, 7)

y = 8 x + 7

Solution steps

Find the slope of

f (x) = 7 e^{x} + x : \frac{df ( x )}{d x} = 7 e^{x} + 1

Compute the slope of

f (x) = 7 e^{x} + x

(0, 7) : m = 8

Find the line with slope m=

8

and passing through

(0, 7) : y = 8 x + 7

y = 8 x + 7

\int \frac{2 - v}{v ^{2} - 1} d v

f (x) = x - 2, g (x) = - x^{2} + x + 2

\int x^{2} x - 4 d x

\int \frac{sin ^{3} ( x )}{cos ^{5} ( x )} d x

What is the tangent of f(x)=7e^x+x,(0,7) ?
The tangent of f(x)=7e^x+x,(0,7) is y=8x+7