What is the limit as x approaches 3 of sqrt(2x^2+1) ?

The limit as x approaches 3 of sqrt(2x^2+1) is square root of 19

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limit as x approaches 3 of sqrt(2x^2+1)

x \to 3 lim (2 x^{2} + 1)

19

Decimal Notation

4.35889 \dots

Solution steps

x \to 3 lim (2 x^{2} + 1)

Plug in the value

x = 3

= 2 \cdot 3^{2} + 1

Simplify

= 19

\frac{d y}{d x} + \frac{2}{x} y = x^{2} y^{3}

\frac{d}{d x} (3 x^{2} + 4 x + 2)

\frac{d}{d x} (1 - (1 - (\frac{x}{y ( x , s )})^{s})^{n})

n = 0 \sum \infty \frac{1}{n + 3}

f (x) = \frac{x}{x ^{2} + 4}

What is the limit as x approaches 3 of sqrt(2x^2+1) ?
The limit as x approaches 3 of sqrt(2x^2+1) is square root of 19