What is the derivative of 3x^2+4x+2 ?

The derivative of 3x^2+4x+2 is 6x+4

What is the first derivative of 3x^2+4x+2 ?

The first derivative of 3x^2+4x+2 is 6x+4

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\frac{d}{d x} (3 x^{2} + 4 x + 2)

6 x + 4

Solution steps

\frac{d}{d x} (3 x^{2} + 4 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (2) = 0

= 6 x + 4 + 0

Simplify

= 6 x + 4

\frac{d}{d x} (1 - (1 - (\frac{x}{y ( x , s )})^{s})^{n})

n = 0 \sum \infty \frac{1}{n + 3}

f (x) = \frac{x}{x ^{2} + 4}

y = 3 + 9 - (x - 3)^{2}

f (x) = \frac{4}{5 x + 1}

What is the derivative of 3x^2+4x+2 ?
The derivative of 3x^2+4x+2 is 6x+4
What is the first derivative of 3x^2+4x+2 ?
The first derivative of 3x^2+4x+2 is 6x+4