What is the derivative of f(x)= 4/(5x+1) ?

The derivative of f(x)= 4/(5x+1) is -(20)/((5x+1)^2)

What is the first derivative of f(x)= 4/(5x+1) ?

The first derivative of f(x)= 4/(5x+1) is -(20)/((5x+1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{4}{5 x + 1}

- \frac{20}{( 5 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{5 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{5 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((5 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 5 x + 1 ) ^{2}} \frac{d}{d x} (5 x + 1)

= - \frac{1}{( 5 x + 1 ) ^{2}} \frac{d}{d x} (5 x + 1)

\frac{d}{d x} (5 x + 1) = 5

= 4 (- \frac{1}{( 5 x + 1 ) ^{2}} \cdot 5)

Simplify

4 (- \frac{1}{( 5 x + 1 ) ^{2}} \cdot 5) : - \frac{20}{( 5 x + 1 ) ^{2}}

= - \frac{20}{( 5 x + 1 ) ^{2}}

x^{2} y^{^{''}} - 2 x y^{^{'}} - 10 y = 0

\int e^{2 x} + x^{2} d x

n = 1 \sum \infty 9 (\frac{1 - 3}{4})^{n}

\int \frac{cos ( x )}{5 - sin ( x )} d x

\frac{3}{( 3 + ( x + 2 ) ^{2} ) ^{\frac{3}{2}}}, 0

What is the derivative of f(x)= 4/(5x+1) ?
The derivative of f(x)= 4/(5x+1) is -(20)/((5x+1)^2)
What is the first derivative of f(x)= 4/(5x+1) ?
The first derivative of f(x)= 4/(5x+1) is -(20)/((5x+1)^2)