What is the derivative of tan^{sec(1/x}(1/x)) ?

The derivative of tan^{sec(1/x}(1/x)) is

What is the first derivative of tan^{sec(1/x}(1/x)) ?

The first derivative of tan^{sec(1/x}(1/x)) is

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\frac{d}{d x} (tan^{s e c (\frac{1}{x})} (\frac{1}{x}))

tan^{s e c (\frac{1}{x})} (\frac{1}{x}) (- \frac{sec ( \frac{1}{x} ) tan ( \frac{1}{x} ) ln ( tan ( \frac{1}{x} ) )}{x ^{2}} - \frac{sec ^{3} ( \frac{1}{x} )}{x ^{2} tan ( \frac{1}{x} )})

Solution steps

\frac{d}{d x} (tan^{s e c (\frac{1}{x})} (\frac{1}{x}))

Apply exponent rule:

a^{b} = e^{b l n (a)}

tan^{s e c (\frac{1}{x})} (\frac{1}{x}) = e^{s e c (\frac{1}{x}) l n (t a n (\frac{1}{x}))}

= \frac{d}{d x} (e^{s e c (\frac{1}{x}) l n (t a n (\frac{1}{x}))})

Apply the chain rule:

e^{s e c (\frac{1}{x}) l n (t a n (\frac{1}{x}))} \frac{d}{d x} (sec (\frac{1}{x}) ln (tan (\frac{1}{x})))

= e^{s e c (\frac{1}{x}) l n (t a n (\frac{1}{x}))} \frac{d}{d x} (sec (\frac{1}{x}) ln (tan (\frac{1}{x})))

\frac{d}{d x} (sec (\frac{1}{x}) ln (tan (\frac{1}{x}))) = - \frac{sec ( \frac{1}{x} ) tan ( \frac{1}{x} ) ln ( tan ( \frac{1}{x} ) )}{x ^{2}} - \frac{sec ^{3} ( \frac{1}{x} )}{x ^{2} tan ( \frac{1}{x} )}

= e^{s e c (\frac{1}{x}) l n (t a n (\frac{1}{x}))} (- \frac{sec ( \frac{1}{x} ) tan ( \frac{1}{x} ) ln ( tan ( \frac{1}{x} ) )}{x ^{2}} - \frac{sec ^{3} ( \frac{1}{x} )}{x ^{2} tan ( \frac{1}{x} )})

e^{s e c (\frac{1}{x}) l n (t a n (\frac{1}{x}))} = tan^{s e c (\frac{1}{x})} (\frac{1}{x})

= tan^{s e c (\frac{1}{x})} (\frac{1}{x}) (- \frac{sec ( \frac{1}{x} ) tan ( \frac{1}{x} ) ln ( tan ( \frac{1}{x} ) )}{x ^{2}} - \frac{sec ^{3} ( \frac{1}{x} )}{x ^{2} tan ( \frac{1}{x} )})

f (x) = x^{4} - 6 x^{3}

\int 7 x^{2} + x x d x

\frac{d y}{d t} = 6 y + cos (3 t), y (0) = \frac{28}{15}

\int 7 5 (8 - 2 x)^{8} d x

f (x) = x^{4} + 6 x^{2} - x, at x = 1

What is the derivative of tan^{sec(1/x}(1/x)) ?
The derivative of tan^{sec(1/x}(1/x)) is
What is the first derivative of tan^{sec(1/x}(1/x)) ?
The first derivative of tan^{sec(1/x}(1/x)) is