What is the integral of sqrt(3+2x) ?

The integral of sqrt(3+2x) is 1/3 (3+2x)^{3/2}+C

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integral of sqrt(3+2x)

\int 3 + 2 x d x

\frac{1}{3} (3 + 2 x)^{\frac{3}{2}} + C

Solution steps

\int 3 + 2 x d x

Apply u-substitution

: \int \frac{u}{2} d u

= \int \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{2} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 3 + 2 x

= \frac{1}{2} \cdot \frac{2}{3} (3 + 2 x)^{\frac{3}{2}}

Simplify

\frac{1}{2} \cdot \frac{2}{3} (3 + 2 x)^{\frac{3}{2}} : \frac{1}{3} (3 + 2 x)^{\frac{3}{2}}

= \frac{1}{3} (3 + 2 x)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{3} (3 + 2 x)^{\frac{3}{2}} + C

\int \frac{2 x + 3}{( x - 1 ) ^{2}} d x

\int \frac{sin ( x )}{1} d x

x \to - 2 lim (\frac{x ^{3} + 8}{x + 2})

x \to 2 - lim (f (x) x)

a^{0.5}

What is the integral of sqrt(3+2x) ?
The integral of sqrt(3+2x) is 1/3 (3+2x)^{3/2}+C