What is the derivative of y= x/3-3/x ?

The derivative of y= x/3-3/x is 1/3+3/(x^2)

What is the first derivative of y= x/3-3/x ?

The first derivative of y= x/3-3/x is 1/3+3/(x^2)

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derivative of

y = \frac{x}{3} - \frac{3}{x}

\frac{1}{3} + \frac{3}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{3} - \frac{3}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x}{3}) - \frac{d}{d x} (\frac{3}{x})

\frac{d}{d x} (\frac{x}{3}) = \frac{1}{3}

\frac{d}{d x} (\frac{3}{x}) = - \frac{3}{x ^{2}}

= \frac{1}{3} - (- \frac{3}{x ^{2}})

Simplify

= \frac{1}{3} + \frac{3}{x ^{2}}

e^{x^{4}} \cdot 4 x^{3}

2 y^{^{''}} - 5 y^{^{'}} - 12 y = 0

x \to 1 lim (e^{2 x^{3} - 2 x})

y^{^{''}} = e^{2 t}

\frac{\partial}{\partial x} (7 x y^{6} + x^{4} y^{4})

What is the derivative of y= x/3-3/x ?
The derivative of y= x/3-3/x is 1/3+3/(x^2)
What is the first derivative of y= x/3-3/x ?
The first derivative of y= x/3-3/x is 1/3+3/(x^2)