What is the derivative of 2x^3-8x ?

The derivative of 2x^3-8x is 6x^2-8

What is the first derivative of 2x^3-8x ?

The first derivative of 2x^3-8x is 6x^2-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 x^{3} - 8 x)

6 x^{2} - 8

Solution steps

\frac{d}{d x} (2 x^{3} - 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (8 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (8 x) = 8

= 6 x^{2} - 8

e^{x} + e^{y} \frac{d y}{d x} = 0

x \to 3 - lim (- x^{2} + 9)

x \to 3 lim (2 x + 1)

\int e^{- c o s (3 x)} sin (3 x) d x

x \frac{d y}{d x} - 2 y = 3 x^{2} + 2 x

What is the derivative of 2x^3-8x ?
The derivative of 2x^3-8x is 6x^2-8
What is the first derivative of 2x^3-8x ?
The first derivative of 2x^3-8x is 6x^2-8