What is the solution for x(dy)/(dx)-2y=3x^2+2x ?

The solution for x(dy)/(dx)-2y=3x^2+2x is y=3x^2ln(x)-2x+c_{1}x^2

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x(dy)/(dx)-2y=3x^2+2x

x \frac{d y}{d x} - 2 y = 3 x^{2} + 2 x

y = 3 x^{2} ln (x) - 2 x + c_{1} x^{2}

Solution steps

x \frac{d y}{d x} - 2 y = 3 x^{2} + 2 x

Solve linear ODE:

y = 3 x^{2} ln (x) - 2 x + c_{1} x^{2}

y = 3 x^{2} ln (x) - 2 x + c_{1} x^{2}

n = 1 \sum \infty \frac{n}{n ^{4} + 1}

f (x) = x^{2} - 4 x, at x = 3

\int (2 x + 1)^{3} d x

n = 1 \sum \infty \frac{n ^{2}}{5 n}

\frac{d}{d t} (\frac{1}{1 + t})

What is the solution for x(dy)/(dx)-2y=3x^2+2x ?
The solution for x(dy)/(dx)-2y=3x^2+2x is y=3x^2ln(x)-2x+c_{1}x^2