What is the d/(dt)(1/(1+t)) ?

The d/(dt)(1/(1+t)) is -1/((1+t)^2)

What is the first d/(dt)(1/(1+t)) ?

The first d/(dt)(1/(1+t)) is -1/((1+t)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (\frac{1}{1 + t})

- \frac{1}{( 1 + t ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{1}{1 + t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} ((1 + t)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 + t ) ^{2}} \frac{d}{d t} (1 + t)

= - \frac{1}{( 1 + t ) ^{2}} \frac{d}{d t} (1 + t)

\frac{d}{d t} (1 + t) = 1

= - \frac{1}{( 1 + t ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( 1 + t ) ^{2}}

f (x) = (x + 2)^{\frac{1}{2}}

n \to \infty lim (\frac{( 5 n )}{5 n + 7})

\frac{\partial}{\partial y} (\frac{9 y}{x})

\int sin (k x) d x

\int (1 - 5 x) d x