What is the derivative of g(x)=-8e^{x^2-1} ?

The derivative of g(x)=-8e^{x^2-1} is -16e^{x^2-1}x

What is the first derivative of g(x)=-8e^{x^2-1} ?

The first derivative of g(x)=-8e^{x^2-1} is -16e^{x^2-1}x

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derivative of

g (x) = - 8 e^{x^{2} - 1}

- 16 e^{x^{2} - 1} x

Solution steps

\frac{d}{d x} (- 8 e^{x^{2} - 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (e^{x^{2} - 1})

Apply the chain rule:

e^{x^{2} - 1} \frac{d}{d x} (x^{2} - 1)

= e^{x^{2} - 1} \frac{d}{d x} (x^{2} - 1)

\frac{d}{d x} (x^{2} - 1) = 2 x

= - 8 e^{x^{2} - 1} \cdot 2 x

Simplify

= - 16 e^{x^{2} - 1} x

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What is the derivative of g(x)=-8e^{x^2-1} ?
The derivative of g(x)=-8e^{x^2-1} is -16e^{x^2-1}x
What is the first derivative of g(x)=-8e^{x^2-1} ?
The first derivative of g(x)=-8e^{x^2-1} is -16e^{x^2-1}x