What is the derivative of (3-2x^3) ?

The derivative of (3-2x^3) is -6(3-2x)^2

What is the first derivative of (3-2x^3) ?

The first derivative of (3-2x^3) is -6(3-2x)^2

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\frac{d}{d x} ((3 - 2 x)^{3})

- 6 (3 - 2 x)^{2}

Solution steps

\frac{d}{d x} ((3 - 2 x)^{3})

Apply the chain rule:

3 (3 - 2 x)^{2} \frac{d}{d x} (3 - 2 x)

= 3 (3 - 2 x)^{2} \frac{d}{d x} (3 - 2 x)

\frac{d}{d x} (3 - 2 x) = - 2

= 3 (3 - 2 x)^{2} (- 2)

Simplify

= - 6 (3 - 2 x)^{2}

f (X) = 7 (X - 5)^{\frac{2}{3}}

y = ln (9 x)

x^{3} - 10 x^{2} + 24 x, - x^{3} + 10 x^{2} - 24 x

n = 1 \sum \infty (- 4)^{- n}

\frac{2 x ^{\frac{3}{2}} - x ^{2} + 4}{x}

What is the derivative of (3-2x^3) ?
The derivative of (3-2x^3) is -6(3-2x)^2
What is the first derivative of (3-2x^3) ?
The first derivative of (3-2x^3) is -6(3-2x)^2