What is the solution for y^'-2/x y=(y^3)/(x^3) ?

The solution for y^'-2/x y=(y^3)/(x^3) is y=(x^2)/(sqrt(-x^2+c_{1))},y=-(x^2)/(sqrt(-x^2+c_{1))}

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y^'-2/x y=(y^3)/(x^3)

y^{^{'}} - \frac{2}{x} y = \frac{y ^{3}}{x ^{3}}

y = \frac{x ^{2}}{- x ^{2} + c _{1}}, y = - \frac{x ^{2}}{- x ^{2} + c _{1}}

Solution steps

y^{'} (x) - \frac{2}{x} y = \frac{y ^{3}}{x ^{3}}

Solve Bernoulli ODE:

y = \frac{x ^{2}}{- x ^{2} + c _{1}}, y = - \frac{x ^{2}}{- x ^{2} + c _{1}}

y = \frac{x ^{2}}{- x ^{2} + c _{1}}, y = - \frac{x ^{2}}{- x ^{2} + c _{1}}

h \to 0 lim (\frac{( e ^{2 h} - 1 )}{h})

x, (x - 2)^{2}

\frac{d}{d y} (ln (\frac{x}{y}))

f (x) = x^{5}, (- 1, - 1)

x \to - \infty lim (e^{2 x})

What is the solution for y^'-2/x y=(y^3)/(x^3) ?
The solution for y^'-2/x y=(y^3)/(x^3) is y=(x^2)/(sqrt(-x^2+c_{1))},y=-(x^2)/(sqrt(-x^2+c_{1))}