What is (\partial)/(\partial x)(x^2+z^2) ?

The answer to (\partial)/(\partial x)(x^2+z^2) is 2x

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(\partial)/(\partial x)(x^2+z^2)

\frac{\partial}{\partial x} (x^{2} + z^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + z^{2})

Treat

z

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (z^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (z^{2}) = 0

= 2 x + 0

Simplify

= 2 x

\frac{1}{x ^{2} ( x ^{2} + 4 x + 13 )}

\int_{0}^{2} 3 x d x

\int (3 u + \frac{1}{u}) d u

f (x) = (x - 1)^{2} + 1, at x = 1

y^{^{'}} + \frac{1}{x} y = 4 x^{2}

What is (\partial)/(\partial x)(x^2+z^2) ?
The answer to (\partial)/(\partial x)(x^2+z^2) is 2x