What is the integral of (3sqrt(u)+1/(sqrt(u))) ?

The integral of (3sqrt(u)+1/(sqrt(u))) is 2u^{3/2}+2sqrt(u)+C

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integral of (3sqrt(u)+1/(sqrt(u)))

\int (3 u + \frac{1}{u}) d u

2 u^{\frac{3}{2}} + 2 u + C

Solution steps

\int 3 u + \frac{1}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 u d u + \int \frac{1}{u} d u

\int 3 u d u = 2 u^{\frac{3}{2}}

\int \frac{1}{u} d u = 2 u

= 2 u^{\frac{3}{2}} + 2 u

Add a constant to the solution

= 2 u^{\frac{3}{2}} + 2 u + C

f (x) = (x - 1)^{2} + 1, at x = 1

y^{^{'}} + \frac{1}{x} y = 4 x^{2}

\frac{\partial ^{2}}{\partial x \partial y} (y^{5} sin (3 x))

n = 1 \sum \infty \frac{n 7 ^{n}}{n !}

\int 7 e^{5 x} d x

What is the integral of (3sqrt(u)+1/(sqrt(u))) ?
The integral of (3sqrt(u)+1/(sqrt(u))) is 2u^{3/2}+2sqrt(u)+C