What is the solution for y^{''}+8y^'=0,y(0)=1,y^'(0)=1 ?

The solution for y^{''}+8y^'=0,y(0)=1,y^'(0)=1 is y=1+1/8-1/8 e^{-8t}

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y^{''}+8y^'=0,y(0)=1,y^'(0)=1

y^{^{''}} + 8 y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = 1

y = 1 + \frac{1}{8} - \frac{1}{8} e^{- 8 t}

Solution steps

y^{''} (t) + 8 y^{'} (t) = 0

Solve linear ODE:

y = 1 + \frac{1}{8} - \frac{1}{8} e^{- 8 t}

y = 1 + \frac{1}{8} - \frac{1}{8} e^{- 8 t}

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What is the solution for y^{''}+8y^'=0,y(0)=1,y^'(0)=1 ?
The solution for y^{''}+8y^'=0,y(0)=1,y^'(0)=1 is y=1+1/8-1/8 e^{-8t}