What is the solution for y^'=(x^3y^3+2x^3)/(y^2) ?

The solution for y^'=(x^3y^3+2x^3)/(y^2) is y=\sqrt[3]{e^{(3x^4-c_{1})/4}-2}

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y^'=(x^3y^3+2x^3)/(y^2)

y^{^{'}} = \frac{x ^{3} y ^{3} + 2 x ^{3}}{y ^{2}}

Solution steps

y^{'} (x) = \frac{x ^{3} y ^{3} + 2 x ^{3}}{y ^{2}}

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x \to 7 + lim (\frac{6 x}{x - 7})

\frac{\partial}{\partial y} (- y^{2})

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What is the solution for y^'=(x^3y^3+2x^3)/(y^2) ?
The solution for y^'=(x^3y^3+2x^3)/(y^2) is y=\sqrt[3]{e^{(3x^4-c_{1})/4}-2}