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Popular >

y^'=x(4-y)

Solution

y^{^{'}} = x (4 - y)

Solution

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 4

Solution steps

y^{'} (x) = x (4 - y)

Solve separable ODE:

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 4

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 4

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Frequently Asked Questions (FAQ)

What is the solution for y^'=x(4-y) ?
The solution for y^'=x(4-y) is y=-e^{-(x^2)/2-c_{1}}+4