What is the derivative of 8x-18x^{-3} ?

The derivative of 8x-18x^{-3} is 8+(54)/(x^4)

What is the first derivative of 8x-18x^{-3} ?

The first derivative of 8x-18x^{-3} is 8+(54)/(x^4)

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derivative of

8 x - 18 x^{- 3}

8 + \frac{54}{x ^{4}}

Solution steps

\frac{d}{d x} (8 x - 18 x^{- 3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) - \frac{d}{d x} (18 x^{- 3})

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (18 x^{- 3}) = - \frac{54}{x ^{4}}

= 8 - (- \frac{54}{x ^{4}})

Simplify

= 8 + \frac{54}{x ^{4}}

3 x^{3} - 2 x, - 3, 3

\frac{\partial}{\partial y} (\frac{1}{t ( y ^{2} - 9 )})

f (x) = \frac{x}{9 - x ^{2}}, g (y) = 0, y = 2

\int e^{- i x} d x

x \to + 1 lim (∣ 2 x ∣)

What is the derivative of 8x-18x^{-3} ?
The derivative of 8x-18x^{-3} is 8+(54)/(x^4)
What is the first derivative of 8x-18x^{-3} ?
The first derivative of 8x-18x^{-3} is 8+(54)/(x^4)