What is area f(x)= x/(sqrt(9-x^2)),g(y)=0,y=2 ?

The answer to area f(x)= x/(sqrt(9-x^2)),g(y)=0,y=2 is No Solution

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area f(x)= x/(sqrt(9-x^2)),g(y)=0,y=2

area

f (x) = \frac{x}{9 - x ^{2}}, g (y) = 0, y = 2

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

0 = 2 :

False

0 = \frac{x}{9 - x ^{2}} : x = 0

2 = \frac{x}{9 - x ^{2}} : x = \frac{6}{5}

Curves not bounded

= No Solution

\int e^{- i x} d x

x \to + 1 lim (∣ 2 x ∣)

\frac{d}{d x} (\frac{x ^{2} - 4}{6 x ^{3} - 2})

\frac{1}{2 x} + \frac{1}{4 x ^{\frac{3}{4}}}

\frac{d}{d x} (\frac{x ^{2} - 2}{- x ^{2} + 1})

What is area f(x)= x/(sqrt(9-x^2)),g(y)=0,y=2 ?
The answer to area f(x)= x/(sqrt(9-x^2)),g(y)=0,y=2 is No Solution