What is the solution for (dy)/(dx)+2y-8e^{-x}=0,y(0)=7 ?

The solution for (dy)/(dx)+2y-8e^{-x}=0,y(0)=7 is y= 8/(e^x)-1/(e^{2x)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+2y-8e^{-x}=0,y(0)=7

\frac{d y}{d x} + 2 y - 8 e^{- x} = 0, y (0) = 7

y = \frac{8}{e ^{x}} - \frac{1}{e ^{2 x}}

Solution steps

\frac{d y}{d x} + 2 y - 8 e^{- x} = 0

Solve linear ODE:

y = \frac{8}{e ^{x}} - \frac{1}{e ^{2 x}}

y = \frac{8}{e ^{x}} - \frac{1}{e ^{2 x}}

x y^{^{'}} + (1 + x cot (x)) y = 0

\int_{0}^{1} (e^{x}) - (x e^{x^{2}}) d x

x \to \infty lim (2 g (x) x)

\frac{d}{d x} (\frac{1}{10} x - \frac{1}{2})

\int \frac{1 + x ^{2}}{x - x ^{3}} d x

What is the solution for (dy)/(dx)+2y-8e^{-x}=0,y(0)=7 ?
The solution for (dy)/(dx)+2y-8e^{-x}=0,y(0)=7 is y= 8/(e^x)-1/(e^{2x)}