What is the derivative of (3x+1^2) ?

The derivative of (3x+1^2) is 6(3x+1)

What is the first derivative of (3x+1^2) ?

The first derivative of (3x+1^2) is 6(3x+1)

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\frac{d}{d x} ((3 x + 1)^{2})

6 (3 x + 1)

Solution steps

\frac{d}{d x} ((3 x + 1)^{2})

Apply the chain rule:

2 (3 x + 1) \frac{d}{d x} (3 x + 1)

= 2 (3 x + 1) \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= 2 (3 x + 1) \cdot 3

Simplify

= 6 (3 x + 1)

\int \frac{200}{16 x ^{2} + 256} d x

\frac{d ^{2} y}{d x ^{2}} = 4 y, y (0) = 0, y^{^{'}} (0) = 1

y^{^{''}} - y^{^{'}} = x e^{x}

12 = \frac{1}{( 22 \cdot 1 0 ^{- 6} )} y + \frac{33000 d y}{d x}

\frac{\partial}{\partial x} (ln (y) + 4 x)

What is the derivative of (3x+1^2) ?
The derivative of (3x+1^2) is 6(3x+1)
What is the first derivative of (3x+1^2) ?
The first derivative of (3x+1^2) is 6(3x+1)