What is the derivative of y=e^{4cos(sqrt(x))} ?

The derivative of y=e^{4cos(sqrt(x))} is -(2e^{4cos(sqrt(x))}sin(sqrt(x)))/(sqrt(x))

What is the first derivative of y=e^{4cos(sqrt(x))} ?

The first derivative of y=e^{4cos(sqrt(x))} is -(2e^{4cos(sqrt(x))}sin(sqrt(x)))/(sqrt(x))

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derivative of

y = e^{4 c o s (x)}

- \frac{2 e ^{4 c o s (x)} sin ( x )}{x}

Solution steps

\frac{d}{d x} (e^{4 c o s (x)})

Apply the chain rule:

e^{4 c o s (x)} \frac{d}{d x} (4 cos (x))

= e^{4 c o s (x)} \frac{d}{d x} (4 cos (x))

\frac{d}{d x} (4 cos (x)) = - \frac{2 sin ( x )}{x}

= e^{4 c o s (x)} (- \frac{2 sin ( x )}{x})

Simplify

e^{4 c o s (x)} (- \frac{2 sin ( x )}{x}) : - \frac{2 e ^{4 c o s (x)} sin ( x )}{x}

= - \frac{2 e ^{4 c o s (x)} sin ( x )}{x}

\int e^{x} + \frac{1}{x} d x

f (x) = sin (cos (x))

\int \frac{3}{x ^{2} + 2} d x

\int 18 sec^{4} (x) d x

h \to 0 lim (sin (\frac{1}{h}))

What is the derivative of y=e^{4cos(sqrt(x))} ?
The derivative of y=e^{4cos(sqrt(x))} is -(2e^{4cos(sqrt(x))}sin(sqrt(x)))/(sqrt(x))
What is the first derivative of y=e^{4cos(sqrt(x))} ?
The first derivative of y=e^{4cos(sqrt(x))} is -(2e^{4cos(sqrt(x))}sin(sqrt(x)))/(sqrt(x))