What is the solution for (x-2)y^'+y=3x^2+2x ?

The solution for (x-2)y^'+y=3x^2+2x is y=(x^3)/(x-2)+(x^2)/(x-2)+(c_{1})/(x-2)

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(x-2)y^'+y=3x^2+2x

(x - 2) y^{^{'}} + y = 3 x^{2} + 2 x

y = \frac{x ^{3}}{x - 2} + \frac{x ^{2}}{x - 2} + \frac{c _{1}}{x - 2}

Solution steps

(x - 2) y^{'} (x) + y = 3 x^{2} + 2 x

Solve linear ODE:

y = \frac{x ^{3}}{x - 2} + \frac{x ^{2}}{x - 2} + \frac{c _{1}}{x - 2}

y = \frac{x ^{3}}{x - 2} + \frac{x ^{2}}{x - 2} + \frac{c _{1}}{x - 2}

n = 0 \sum \infty \frac{1}{( 2 n + 1 ) ^{4}}

x + 3 y = 34, x + 6 = y^{2}

\frac{d}{d x} (9 x^{2} e^{- x})

f (x) = \frac{5}{2} + \frac{3}{2} x

What is the solution for (x-2)y^'+y=3x^2+2x ?
The solution for (x-2)y^'+y=3x^2+2x is y=(x^3)/(x-2)+(x^2)/(x-2)+(c_{1})/(x-2)