What is implicit 2x^2+2x+xy=2 ?

The answer to implicit 2x^2+2x+xy=2 is (dy}{dx}=\frac{-4x-y-2)/x

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implicit 2x^2+2x+xy=2

implicit derivative

2 x^{2} + 2 x + x y = 2

\frac{d y}{d x} = \frac{- 4 x - y - 2}{x}

Solution steps

2 x^{2} + 2 x + x y = 2

Treat

y

y (x)

Differentiate both sides:

4 x + 2 + y + x \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- 4 x - y - 2}{x}

\frac{d y}{d x} = \frac{- 4 x - y - 2}{x}

f (x) = x^{- \frac{1}{9}}

\frac{( s - 5 )}{( s ^{2} - 6 s + 25 )}

\frac{d}{d x} (\frac{6 x ^{7}}{5 tan ( x )})

\frac{d}{d x} (\frac{2 x + 5 x ^{- \frac{2}{5}}}{x ^{2} + 1})

\frac{\partial}{\partial x} (x^{4} y^{3} - 4 x^{2} y + y^{5})

What is implicit 2x^2+2x+xy=2 ?
The answer to implicit 2x^2+2x+xy=2 is (dy}{dx}=\frac{-4x-y-2)/x