What is the solution for (dy)/(dx)+8y-8e^{-5x}=0,y(0)= 5/3 ?

The solution for (dy)/(dx)+8y-8e^{-5x}=0,y(0)= 5/3 is y= 8/(3e^{5x)}-1/(e^{8x)}

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(dy)/(dx)+8y-8e^{-5x}=0,y(0)= 5/3

\frac{d y}{d x} + 8 y - 8 e^{- 5 x} = 0, y (0) = \frac{5}{3}

y = \frac{8}{3 e ^{5 x}} - \frac{1}{e ^{8 x}}

Solution steps

\frac{d y}{d x} + 8 y - 8 e^{- 5 x} = 0

Solve linear ODE:

y = \frac{8}{3 e ^{5 x}} - \frac{1}{e ^{8 x}}

y = \frac{8}{3 e ^{5 x}} - \frac{1}{e ^{8 x}}

n = 1 \sum \infty \frac{4}{n ^{4}}

y = \frac{6}{x - 1}, (3, 3)

\int \frac{1}{y ^{2} + 9} d y

(14 x - x^{2})^{3}

f (x) = \frac{1}{x}, at x = 9

What is the solution for (dy)/(dx)+8y-8e^{-5x}=0,y(0)= 5/3 ?
The solution for (dy)/(dx)+8y-8e^{-5x}=0,y(0)= 5/3 is y= 8/(3e^{5x)}-1/(e^{8x)}