What is the tangent of f(x)=2x^4,\at x=-2,32 ?

The tangent of f(x)=2x^4,\at x=-2,32 is y=-64x-96

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tangent of f(x)=2x^4,\at x=-2,32

tangent of

f (x) = 2 x^{4}, at x = - 2, 32

y = - 64 x - 96

Solution steps

Find the tangent point:

(- 2, 32)

Find the slope of

f (x) = 2 x^{4} : \frac{df ( x )}{d x} = 8 x^{3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 64

Find the line with slope m=

- 64

and passing through

(- 2, 32) : y = - 64 x - 96

y = - 64 x - 96

\frac{6 x ^{2} + 6 x + 8}{x}

\int csc^{4} (9 x) d x

(x - 1) e^{x}

\frac{\partial}{\partial x} (7 x y + x cos (x))

- x^{2} + 4, 3 x

What is the tangent of f(x)=2x^4,\at x=-2,32 ?
The tangent of f(x)=2x^4,\at x=-2,32 is y=-64x-96