What is the integral from 0 to \sqrt[3]{7 of}x^2 ?

The integral from 0 to \sqrt[3]{7 of}x^2 is 7/3

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integral from 0 to \sqrt[3]{7 of}x^2

\int_{0}^{37} x^{2} d x

\frac{7}{3}

Decimal

2.33333 \dots

Solution steps

\int_{0}^{37} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{37}

= [\frac{x ^{3}}{3}]_{0}^{37}

Compute the boundaries:

\frac{7}{3}

= \frac{7}{3}

\frac{3}{4 x + 1}

\frac{d}{d x} (\frac{2 x}{x ^{2} + 1})

\frac{d}{d x} ((x - 4)^{3} e^{- 4 x})

\frac{d y}{d x} = e^{3 x + 5 y}

\int 4 tan^{3} (x) sec^{2} (x) d x

What is the integral from 0 to \sqrt[3]{7 of}x^2 ?
The integral from 0 to \sqrt[3]{7 of}x^2 is 7/3