What is the integral from 0 to pi/4 of 10sec^2(x) ?

The integral from 0 to pi/4 of 10sec^2(x) is 10

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integral from 0 to pi/4 of 10sec^2(x)

\int_{0}^{\frac{π}{4}} 10 sec^{2} (x) d x

10

Solution steps

\int_{0}^{\frac{π}{4}} 10 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int_{0}^{\frac{π}{4}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 10 [tan (x)]_{0}^{\frac{π}{4}}

Compute the boundaries:

1

= 10 \cdot 1

Simplify

= 10

\frac{\partial}{\partial x} (cos (x e^{x y}))

n = 1 \sum \infty \frac{4}{3 n}

x \to 0 lim (x^{4} cos (\frac{9}{x}))

t - sin (t)

ln (2 x + 1)

What is the integral from 0 to pi/4 of 10sec^2(x) ?
The integral from 0 to pi/4 of 10sec^2(x) is 10