What is the first derivative of 4x+8 ?

The first derivative of 4x+8 is 4

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derivative of 4x+8

\frac{d}{d x} (4 x + 8)

4

Solution steps

\frac{d}{d x} (4 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) + \frac{d}{d x} (8)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (8) = 0

= 4 + 0

Simplify

= 4

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