What is the sum from n=1 to infinity of 5/([pi^2]) ?

The sum from n=1 to infinity of 5/([pi^2]) is diverges

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sum from n=1 to infinity of 5/([pi^2])

n = 1 \sum \infty \frac{5}{[ π ^{2} ]}

diverges

Solution steps

n = 1 \sum \infty \frac{5}{[ π ^{2} ]}

Every infinite sum of a non-zero constant diverges

= diverges

\frac{d}{d x} (sin (x) - sin^{2} (x))

f (x) = 8 x^{4}, at x = 2

y = x^{3} (2 x - 5)^{4}

\frac{d}{d x} (2 x^{2} - 7)

- e^{x} y \frac{d y}{d x} = e^{- y} + e^{- 2 x - y}

What is the sum from n=1 to infinity of 5/([pi^2]) ?
The sum from n=1 to infinity of 5/([pi^2]) is diverges