What is the integral of 1/(11x-5) ?

The integral of 1/(11x-5) is 1/11 ln|11x-5|+C

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integral of 1/(11x-5)

\int \frac{1}{11 x - 5} d x

\frac{1}{11} ln ∣ 11 x - 5 ∣ + C

Solution steps

\int \frac{1}{11 x - 5} d x

Apply u-substitution

: \int \frac{1}{11 u} d u

= \int \frac{1}{11 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{11} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{11} ln ∣ u ∣

Substitute back

u = 11 x - 5

= \frac{1}{11} ln ∣ 11 x - 5 ∣

Add a constant to the solution

= \frac{1}{11} ln ∣ 11 x - 5 ∣ + C

4 y^{^{''}} + 28 y = 0

\frac{\partial}{\partial x} (f (x, y) x (x, y))

\frac{d y}{d x} = \frac{x + y + 1}{x}

\frac{d}{d x} (arctan (\frac{( x - 1 )}{( x + 1 )}))

x \to 1 - lim (g (x))

What is the integral of 1/(11x-5) ?
The integral of 1/(11x-5) is 1/11 ln|11x-5|+C