What is (\partial)/(\partial x)(x^4-ax^2+a^2) ?

The answer to (\partial)/(\partial x)(x^4-ax^2+a^2) is 4x^3-2ax

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(\partial)/(\partial x)(x^4-ax^2+a^2)

\frac{\partial}{\partial x} (x^{4} - a x^{2} + a^{2})

4 x^{3} - 2 a x

Solution steps

\frac{\partial}{\partial x} (x^{4} - a x^{2} + a^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{4}) - \frac{\partial}{\partial x} (a x^{2}) + \frac{\partial}{\partial x} (a^{2})

\frac{\partial}{\partial x} (x^{4}) = 4 x^{3}

\frac{\partial}{\partial x} (a x^{2}) = 2 a x

\frac{\partial}{\partial x} (a^{2}) = 0

= 4 x^{3} - 2 a x + 0

Simplify

= 4 x^{3} - 2 a x

n = 1 \sum \infty n^{\frac{3}{2}}

t \cdot \frac{d y}{d t} = t^{3} + 11 t^{3} y

2 x^{5} + 3 x^{3} - 3

x \to \infty lim (- 3^{- x})

f (x) = x (x^{- 1} + 7)

What is (\partial)/(\partial x)(x^4-ax^2+a^2) ?
The answer to (\partial)/(\partial x)(x^4-ax^2+a^2) is 4x^3-2ax