What is the solution for y^'=x-(xy)/(x^2-3) ?

The solution for y^'=x-(xy)/(x^2-3) is y=(x^2-3)/3+(c_{1})/(sqrt(x^2-3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=x-(xy)/(x^2-3)

y^{^{'}} = x - \frac{x y}{x ^{2} - 3}

y = \frac{x ^{2} - 3}{3} + \frac{c _{1}}{x ^{2} - 3}

Solution steps

y^{'} (x) = x - \frac{x y}{x ^{2} - 3}

Solve linear ODE:

y = \frac{x ^{2} - 3}{3} + \frac{c _{1}}{x ^{2} - 3}

y = \frac{x ^{2} - 3}{3} + \frac{c _{1}}{x ^{2} - 3}

f (t) = 4 t t + t

\frac{d}{d x} (\frac{5}{x ^{2} + 16})

\frac{d}{d x} (\frac{2}{1 - x})

x \to - 5 - lim (\frac{- 4 x}{x + 5})

\int \frac{ln ( t ) t ^{- 1}}{- 3} d t

What is the solution for y^'=x-(xy)/(x^2-3) ?
The solution for y^'=x-(xy)/(x^2-3) is y=(x^2-3)/3+(c_{1})/(sqrt(x^2-3))