What is the derivative of x^3-12x^2+36x ?

The derivative of x^3-12x^2+36x is 3x^2-24x+36

What is the first derivative of x^3-12x^2+36x ?

The first derivative of x^3-12x^2+36x is 3x^2-24x+36

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\frac{d}{d x} (x^{3} - 12 x^{2} + 36 x)

3 x^{2} - 24 x + 36

Solution steps

\frac{d}{d x} (x^{3} - 12 x^{2} + 36 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (12 x^{2}) + \frac{d}{d x} (36 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (12 x^{2}) = 24 x

\frac{d}{d x} (36 x) = 36

= 3 x^{2} - 24 x + 36

9 (5 x^{4} ln (7 x) + x^{4})

\int \frac{9 - x ^{2}}{x ^{4}} d x

\frac{d}{d x} (lo g_{2} (x^{3}))

100 - x^{2}

\int_{1}^{2} \frac{v ^{3} + 3 v ^{6}}{v ^{4}} d v

What is the derivative of x^3-12x^2+36x ?
The derivative of x^3-12x^2+36x is 3x^2-24x+36
What is the first derivative of x^3-12x^2+36x ?
The first derivative of x^3-12x^2+36x is 3x^2-24x+36