What is the derivative of f(x)=(x-3)(4x+2) ?

The derivative of f(x)=(x-3)(4x+2) is 8x-10

What is the first derivative of f(x)=(x-3)(4x+2) ?

The first derivative of f(x)=(x-3)(4x+2) is 8x-10

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derivative of

f (x) = (x - 3) (4 x + 2)

8 x - 10

Solution steps

\frac{d}{d x} ((x - 3) (4 x + 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x - 3, g = 4 x + 2

= \frac{d}{d x} (x - 3) (4 x + 2) + \frac{d}{d x} (4 x + 2) (x - 3)

\frac{d}{d x} (x - 3) = 1

\frac{d}{d x} (4 x + 2) = 4

= 1 \cdot (4 x + 2) + 4 (x - 3)

Simplify

1 \cdot (4 x + 2) + 4 (x - 3) : 8 x - 10

= 8 x - 10

f (x) = 2 sin^{2} (3 x) + 2 cos^{2} (3 x)

\int_{- 2}^{2} x + 2 d x

f (x) = (\frac{x - 4}{x + 4})^{4}

\int_{0}^{1} \frac{1}{1 + sin ( 2 x )} d x

\int \frac{( x + 6 )}{( x + 7 )} d x

What is the derivative of f(x)=(x-3)(4x+2) ?
The derivative of f(x)=(x-3)(4x+2) is 8x-10
What is the first derivative of f(x)=(x-3)(4x+2) ?
The first derivative of f(x)=(x-3)(4x+2) is 8x-10