What is the tangent of f(x)=(3x)/(x^2-6),(3,3) ?

The tangent of f(x)=(3x)/(x^2-6),(3,3) is y=-5x+18

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tangent of f(x)=(3x)/(x^2-6),(3,3)

tangent of

f (x) = \frac{3 x}{x ^{2} - 6}, (3, 3)

y = - 5 x + 18

Solution steps

Find the slope of

f (x) = \frac{3 x}{x ^{2} - 6} : \frac{df ( x )}{d x} = \frac{3 ( - x ^{2} - 6 )}{( x ^{2} - 6 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(3, 3) : y = - 5 x + 18

y = - 5 x + 18

y = \frac{x ^{5}}{5 - x ^{4}}

\frac{d}{d x} (64 - x^{2})

e^{7 x} cos (10 x)

\frac{d}{d x} (sin^{2} (2 x^{3} + 3 x))

y = - 2 x^{2} + 24

What is the tangent of f(x)=(3x)/(x^2-6),(3,3) ?
The tangent of f(x)=(3x)/(x^2-6),(3,3) is y=-5x+18