What is the limit as h approaches 0 of ((3+h)^3-9)/h ?

The limit as h approaches 0 of ((3+h)^3-9)/h is diverges

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limit as h approaches 0 of ((3+h)^3-9)/h

h \to 0 lim (\frac{( 3 + h ) ^{3} - 9}{h})

diverges

Solution steps

h \to 0 lim (\frac{( 3 + h ) ^{3} - 9}{h})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

h \to 0 + lim (\frac{( 3 + h ) ^{3} - 9}{h}) = \infty

h \to 0 - lim (\frac{( 3 + h ) ^{3} - 9}{h}) = - \infty

= diverges

\frac{\partial}{\partial x} (3 x^{2} - 4 x y + x yz)

y^{^{'}} = x^{2} - 2

\frac{1}{x + 4}, at x = 5

ln (x^{3} + 2 x^{2} + 2 x)

\int \frac{4 x}{x - 1} d x

What is the limit as h approaches 0 of ((3+h)^3-9)/h ?
The limit as h approaches 0 of ((3+h)^3-9)/h is diverges