What is the sum from n=0 to infinity of 1/(n^{1.01)} ?

The sum from n=0 to infinity of 1/(n^{1.01)} is converges

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sum from n=0 to infinity of 1/(n^{1.01)}

n = 0 \sum \infty \frac{1}{n ^{1.01}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{1.01}}

Apply p-Series Test:

converges

= converges

x \to 5 lim (x^{2} - 3 x)

x \to 2.99 lim (1 + x)

\int \frac{1}{1 + 1 + x} d x

3 x^{2} - 6

\int (x - 1)^{2} e^{x} d x

What is the sum from n=0 to infinity of 1/(n^{1.01)} ?
The sum from n=0 to infinity of 1/(n^{1.01)} is converges